Heat of Reaction.

>>> heating plant of Reaction Aim: To determine the catch chevvy of reaction of NaOH with HCl Apparatus\Materials: Polythene Cup, Thermometer, Measuring Cylinder, NaOH, HCl. Procedure: (1) 25cm of HCl was situated in polythene cup, (2) HCl was left to stand for 5 proceedings and then the temperature was taken (3) Steps 1-2 was repeat with NaOH instead of HCl, (4) NaOH was added to HCl in polythene cup and stirred for 5minutes and the highest temperature the liquid rose to was recorded. Results: initial temperature of NaOH - 32? Initial temperature of HCl - 31? Final temperature of mixture - 38? Temperature wage hike for NaOH = 6? Temperature rise for HCl = 7? book of account of mixture = 50cm Mass of resultant = 50g 1 cm of solution has a mass of 1g subprogram of moles present in 25cm of NaOH = .0025moles Heat produced = 1365KJ Calculations: (1) Mass of 1cm of solution = 1g since the dumbness of the solution is 1g per cm, (2) Number of moles of NaOH = volume incmxconcentration in moles per dm 1000 cm = (25 x .1)/1000 = .0025moles (3) Heat produced = MC?? of NaOH+ MC?? of HCl = .

025kg X 4200 X (38?- 32?) NaOH = 630J (NaOH) = 025kg X 4200 X (38?- 31?) HCl = 735J (HCl) = 630J (NaOH) + 735J (HCl) = 1365J Conclusion: An exothermal reaction takes place when NaOH is complicated with HCl. The amount of heat produced when .0025 moles of NaOH is mixed which .0025 Moles of HCl is equal to 1365J and the amount of heat that get out be produced when 1mole of NaOH reacts with 1mole of HCL will be equal to ((1 moles\ .1mole) X 1356j), 546KJ superb lab. Well organize d. acceptable conclusion. And excellent c! alculations!! Needs sources If you want to get a love life essay, order it on our website: OrderEssay.net

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